theres a few people putting various figures on rotary displacement as far as a replacement motor calculation.
this may help its nsw rta on light vehicle standards.
http://www.rta.nsw.gov.au/registration/ ... v_2007.pdf
it says capacity for rotary engines is the total of all rotors x 2
anywho read page 3 it has some interesting reading on tare weight and max engine capacity, turbo and non turbo
but it does have a note under the table that these limits do not apply to 4wd, light truck and busses up to 4.5gvm
but I have never found any rules for them. maybe its on a per vehicle basis.
going by the calcs for turbo (tare kg) x 2.5 = capacity (cc)
a 13b would be all rotors 1.3L x 2 = 2.6L
if it were a 980kg sierra x 2.5 = 2450ml
so a 980kg sierra can have 2.45 turbo and a 13b rotor is equivalant to 2.6L engine
only just misses. but the bit that gets me is the note about 4wd and busses and truck.
just to add a bit more confusion
enjoy ashley