Outer Limits 4x4 Board

I am trying to check a bearing preload, the book says - 30kg/cm force to turn.

from this i gather that with a lever 1cm long 30kg would be needed to turn it. How do i work out the force needed at 4 cm ?

even better - can any one convert this to foot pounds so i can use a torque wrench.

Yes i suck at maths.

thanks

about 2.2 foot pounds

30 x 4 maybe

30kg/30cm = 1foot/kgs 1kg = 2.22 pounds

so yea izuzu rover is right about

2.2 foot pounds

popeye wrote:I am trying to check a bearing preload, the book says - 30kg/cm force to turn.

from this i gather that with a lever 1cm long 30kg would be needed to turn it. How do i work out the force needed at 4 cm ?

even better - can any one convert this to foot pounds so i can use a torque wrench.

Yes i suck at maths.

thanks

That would be 30kg.cm, and you are correct about the 30kg at 1cm.
At 4cm you need (30kg.cm)/4cm = 7.5kg of force.

Alternatively, as superzuki explained it: 30kg.cm = 1kg at 30cm. In round figures, thats 2.2 pounds at one foot = 2.2 lb.ft of torque.

Isuzurover was right!

Scott

thanks,

as my wrench won't go low as 2.2 foot pounds, I'll hang a 1kg weight 30cm from the centre point to set / check the preload.

all good