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Redarc wiring question

For all things Electrical.

Moderator: -Scott-

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Redarc wiring question

Post by antt »

i'm gettin a redarc dual battery controllor this week, and the guy over the phone said that its possible to wire it so that when ya press a button the 2nd battery can be used to fire the motor. just wondering how its done if anyone on here as this setup
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Post by shorty_f0rty »

http://www.redarc.com.au/smartstart-techspec.pdf

wiring diagram is on page 3 for the starter switch..
Built, not bought!
'84 BJ42 - sold! :(
'79 Coiled and turbo diesel'd FJ55
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Post by antt »

cheers mate, only prob is i'm having drama's with adobe not opening pdf's now :cry:
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Post by Utemad »

I just got two of these. They have a blue wire coming out of them that you wire to +ve through your switch. It's that simple. All it is doing is closing the solenoid so you are actually starting from both batteries.
I didn't bother as I can't see my 2nd battery systm starting a 7.3L V8 diesel :D

If you do this of course you need to make sure that the cabling used to wire your second battery is up to the task of starting your car.

You can also do this
http://www.redarc.com.au/sbi_start_assist.pdf
to always start from both batteries.
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Post by antt »

ok, i got the thing during the week and went to wire it in today, but i want to also wire in the 'status indicator' led that shows when the solenoid is open.

to do this it says i have to get a 1k2 resistor and put in in between the redarc and the swich. so i went to dicksmiths today and asked for a 1k2 resistor, and they gave me a little tiny diode resistor (the type with the different coloured bands around it). but when i got it home, my mate said i needed a 'ballast resistor' which apparently is like a porcelin thing or something.

so who's right? can i use my little diode resistor, or do i need to get on of these 'ballast resistors' :?
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Post by charterboat »

The one you have got should be OK. I used one in the exact same situation with a LED and it works great.
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Post by -Scott- »

Antt, your mate is full of something.

12V across a 1k2 resistor will flow 10mA, which is low current even for an LED. At this level power dissipation in the resistor is 120mW, or a bit under 1/8W. Your resistor is probably 1/4W (could be higher), so you're laughing.

On the PDF problem, my old computer was doing that - I had to right click and "Save Target As" to download the file, then view it. I finally tried to fix it, and the computer now locks up at random intervals. :bad-words:

Good luck,

Scott
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Post by antt »

cheers guys :)
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